Question

two angles of a quadrilateral are 68° and 76°.If the other angles are in ratio 5:7 ,find the measure of each of them

Answer 1

let third angle=5x
and fourth angle=7x
a.t.q.
5x+7x+68‌+76=360
12x+144=360
12x=360-144
12x=216
x=216/12
x=18
5x=5*18=90
7x=7*18=126

Answer 2

Your answer is here

Given,

Two angles of quadrilateral = 68 °and 76°

Let the measure of third and fourth

angle be (5x)° and (7x)°

We know that sum of all angles of a

quadrilateral is 360°

68° + 76° + 5x° + 7x° = 360°

144° + 12x° = 360°

12x° = 360° – 144°

12x° = 216°

x° = 216° / 12°

x° = 18°

Required angles

5x = ( 5 × 18 ) ° = 90°

7x = ( 7 × 18 ) ° = 126°

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I hope it will help you

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