Two angles of a quadrilateral are 72° and 56° respectively and the remaining two angles are in the ratio 3:5.Find the measure of each angle of the quadrilateral
Answers
Answered by
133
let the unknown angles be 3x and 5x . so 3x+5x+72+56=360
8x+128=360
8x=360-128
8x=232
x=232/8
x=29
3x=29×3=87
5x=29×5=145
8x+128=360
8x=360-128
8x=232
x=232/8
x=29
3x=29×3=87
5x=29×5=145
Answered by
54
Dear Student,
◆ Answer -
87° and 145°
● Explanation -
Given that angles of a quadrilateral are 72° and 56°. Suppose x be a common multiple such that other two angles are 3x and 5x.
We know that, sum of all angles of quadrilateral is 360°.
72 + 56 + 3x + 5x = 360
128 + 8x = 360
8x = 360 - 128
8x = 232
x = 232 / 8
x = 29°
So, other two angles will be -
3x = 3×29° = 87°
5x = 5×29° = 145°
Hence, other two angles are 87° and 145°.
Thanks dear. Hope this helps you...
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