Question

two angles of a quadrilateral are 80° and 180° the other two angles are equal. find the other two angles​

Answer 1

Angle 1 = 80
Angle 2 = 180
Angle 3 = x
Angle 4 = x

The sun of the angles of quadrilateral = 360
80 + 180 + x + x = 360
260 + 2x = 360
2x = 360 - 260
2x = 100
x = 50

Answer 2

$\large{\underline{\underline{ \bf{⎆Question:-}}}}$

• Two angles of a quadrilateral are 80° and 180° the other two angles are equal. Find the other two angles.

$\large{\underline{\underline{ \bf{☂Solution:-}}}}$

$➥ \tt{Let \: the\:angels\:be\:∠A\:,\:∠B\:,\:∠C\: and \:∠D \: respective}$

$\pink{ \small \underline{ \mathbb{\underline{ ✰ Given\:two\:angles\:are\:equal : }}}}$

$➫\: \tt{Then\:,\: ∠A\:=\:∠B\:=\:x}$

$➫\: \tt{Also\:,\: ∠C\:=\:80° \:and \:∠D\:=\:180°}$

$\small\fbox\red{ ✰ Sum of angles of quadrilateral = 360⁰ }$

$\tt{∴∠A \: + \: ∠B \: +∠C+∠D \: = \: 360⁰}$

$⇝ \tt{x + x + {80}^{0} + \: {180}^{0} = {360}^{0} }$

$⇝ \tt{ 2x + {260}^{0} + = {360}^{0} }$

$⇝ \tt{ 2x = {360}^{0} - {260}^{0} }$

$⇝ \tt{ 2x = {100}^{0} }$

$⇝ \tt{ x = {50}^{0} }$

• Hence , the other two angles are 50⁰.