two angles of a quadrilateral are 88° and76°.If the othertwoangles are in the ratio 5:7,find the measure of each of them
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Answered by
7
Hi!!
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Since the sum of angles of a quadrilateral = 360°
=) 88° + 76° + sum of other two angles = 360°
=) 164° + sum of other two angles = 360°
=) Sum of other two angles = 360° - 164°
=) Sum of other two angles = 196°
Let the meet of ratio of angles be x.
=) 5x + 7x = 196°
=) 12x = 196°
=) x = 196°/12
Hence angles are 5* 196°/12 and 7 * 196°/12
= 980°/12 and 1372°/12
Hope it's helpful to u.
------------
Since the sum of angles of a quadrilateral = 360°
=) 88° + 76° + sum of other two angles = 360°
=) 164° + sum of other two angles = 360°
=) Sum of other two angles = 360° - 164°
=) Sum of other two angles = 196°
Let the meet of ratio of angles be x.
=) 5x + 7x = 196°
=) 12x = 196°
=) x = 196°/12
Hence angles are 5* 196°/12 and 7 * 196°/12
= 980°/12 and 1372°/12
Hope it's helpful to u.
aryan503:
hello
Answered by
9
Here is your answer
We know sum of all angles of a quadrilateral is 360°.
If angle 1 =88°
Angle 2= 76°
And the eatio of other two angles is 5:7
Then let the third angle be 5x
And fourth angle be 7x
So now 88° +76°+5x ° 7x° = 360°
164°+12x=360°
12x=360°-164°
12x= 196°
x= 196/12
x=16.34
Hence fill the value of x
Angle 3 = 5×16.34
=81.65
Angle 4 = 7×16.34
114.31
We know sum of all angles of a quadrilateral is 360°.
If angle 1 =88°
Angle 2= 76°
And the eatio of other two angles is 5:7
Then let the third angle be 5x
And fourth angle be 7x
So now 88° +76°+5x ° 7x° = 360°
164°+12x=360°
12x=360°-164°
12x= 196°
x= 196/12
x=16.34
Hence fill the value of x
Angle 3 = 5×16.34
=81.65
Angle 4 = 7×16.34
114.31
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