Math, asked by aryan503, 1 year ago

two angles of a quadrilateral are 88° and76°.If the othertwoangles are in the ratio 5:7,find the measure of each of them

Answers

Answered by Anonymous
7
Hi!!

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Since the sum of angles of a quadrilateral = 360°

=) 88° + 76° + sum of other two angles = 360°

=) 164° + sum of other two angles = 360°

=) Sum of other two angles = 360° - 164°

=) Sum of other two angles = 196°

Let the meet of ratio of angles be x.

=) 5x + 7x = 196°

=) 12x = 196°

=) x = 196°/12

Hence angles are 5* 196°/12 and 7 * 196°/12

= 980°/12 and 1372°/12

Hope it's helpful to u.

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Answered by natasha41
9
Here is your answer
We know sum of all angles of a quadrilateral is 360°.
If angle 1 =88°
Angle 2= 76°
And the eatio of other two angles is 5:7
Then let the third angle be 5x
And fourth angle be 7x

So now 88° +76°+5x ° 7x° = 360°

164°+12x=360°
12x=360°-164°
12x= 196°
x= 196/12
x=16.34
Hence fill the value of x
Angle 3 = 5×16.34
=81.65

Angle 4 = 7×16.34
114.31
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