Two angles of a quadrilateral are equal and the third angle is 130°. if the forth angle is less than each of the equal angles by 10°, find the remaining angles of the quadrilaterals.
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Let the equal angles be x
Therefore fourth angle be x - 10
ATQ-
x + x + 130 + x - 10 = 360( sum of angles of quadrilateral is 360 degree )
3x + 120 = 360
3x = 360 - 120
3x = 240
x = 240÷3
x = 80
therefore angle 1 and 2 = 80 degree
and angle fourth = 80 - 10 = 70 degree
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