two angles of a trangle are equal at the third angle is greater than each one of them by 18°. find the angles
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36 degree of one angle
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Hello!
Let each of the equal angles be x°
The third angle=(x+18)°
Sum of all the angles of a triangle is 180°
THEREFORE
BTP,
x+x+x+18=180
=>3x+18=180
=>3x=180-18
=>3x=162
=>x=162/3
=>x=54
Each of the equal angles = 54°
The third angle = (54+18)° = 72°
ALL THE ANGLES OF THE TRIANGLE ARE: 54°,54°,72°
__________________________________________________
HOPE THIS HELPS U...☺
Let each of the equal angles be x°
The third angle=(x+18)°
Sum of all the angles of a triangle is 180°
THEREFORE
BTP,
x+x+x+18=180
=>3x+18=180
=>3x=180-18
=>3x=162
=>x=162/3
=>x=54
Each of the equal angles = 54°
The third angle = (54+18)° = 72°
ALL THE ANGLES OF THE TRIANGLE ARE: 54°,54°,72°
__________________________________________________
HOPE THIS HELPS U...☺
shubhamyadav1:
thank
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