Question

TWO ANGLES OF A TRIANGLE ARE EQUAL AND THE THIRD ANGLE IS LESSER THAN EACH OF THESE ANGLES BY 15°. FIND ALL TYE ANGLES OF THE TRIANGLE.​

Answer 1

Answer:

1st angle be x

2nd angle be x

3rd angle be x-15

ATQ, x+x+x-15=180

3x=195

x=65

1st angle =65°

2nd angle=65°

3rd angle=65-50°,==50°