Question

two angles of a triangle are equal and the third angle is greater than each of equal angle by 30 degree determine all the angles of the triangle​

Answer 1

Answer:

let the equal angles be x

so; ATQ

third angle = x +30

asp of triangle

x+x+x+30 = 180

3x= 150

x= 50

so equal angles are 50

& other angle is 80 (50 +30)

Answer 2

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Refer to the attachment..