Question

two angles of a triangle are equal and the third angle is greater than each one of them by 18 degree find the angles​

Answer 1

Given

ABC is an isosceles triangle

angle A =angle B

Angle C = 18+angle A

Angle C = 18+angle B

To find

Angles of triangle ABC

Solution

A+B+C=180°.........(sum of interior anglesof triangle)

A+A+C=180°

2A+C=180°

2A+18+A=180

3A+18=180

3A=162

A=54°

The angles are:

Angle A=54°

Angle B=54°

Angle C=72°

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