Math, asked by suhanikumari1409, 6 months ago

two angles of a triangle are equal and the third angle is greater than each one of them by 18.Find the angles. ​

Answers

Answered by hanshu1234
1

Step-by-step explanation:

Consider ∠A and ∠B in a triangle is x∘

We know that the sum of all the angles in a triangle is 180∘.

So we can write it as

∠A+∠B+∠C=180∘

By substituting the values

x∘+x∘+∠C=180∘

By addition

2x∘+∠C=180∘..(1)

According to the question we get

∠C=x∘+18∘.(2)

By substituting (2) in (1) we get

2x∘+x∘+18∘=180∘

On further calculation

3x∘+18∘=180∘

By subtraction

3x∘=180∘−18∘

3x∘=162∘

By division

x∘=162/3

x∘=54∘

By substituting the values of x

∠A=∠B=54∘

∠C=54∘+18∘=72∘

Therefore, ∠A=54

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