Question

Two angles of a triangle are equal and the third angle is greater than each of these angles by 30°. Find all the
angles of the triangle.​

Answer 1

Answer:

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Step-by-step explanation:

Let the equal angles of the triangle be x.

x + x + (x + 30) = 180 (Angle sum property)

x + x + x + 30 = 180

3x + 30 = 180

3x = 180 - 30

3x = 150

x = $\frac{150}{3}$

x = 50°

1st angle = 50°

2nd angle = 50°

3rd angle = 50 + 30 = 80°

Answer 2

We Can Equate it as:
x + x + ( x + 30 ) = 180
2x + ( x + 30 ) = 180
2x + x + 30 = 180
3x + 30 = 180
3x = 180 - 30
3x = 150
x = 150/3
x = 50

2 Angles are equal so their measures are equal too that is x = 50 only
Third angle is greater than these two angles by 30 so ( x + 30 ) = 50 + 30 = 80

Let us check whether the sum of the angles is 180:
50 + 50 + 80
100 + 80
180

Hope it helps you