Question

two angles of a triangle are equal and the third angle is greater than each one of them by 18 degree. find the angles

Answer 1

Let each equal be x, and other angle be (x + 18)°


We know, sum of all angles of a triangle = 180°



x + x + (x + 18) = 180

x + x + x + 18 = 180

3x = 180 - 18


3x = 162

$x = \frac{162}{3}$
x = 54°


Angles are :
x = 54°
x = 54°
x + 18 = 54 + 18 = 72°




I hope this will help you



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Answer 2

Answer:

Let two angles be x°

So now, x° + x° + x° + 18 = 180°

x+ 18 because third angle is greater by 18°

Therefore, x + x + x +18 = 180°

3x + 18= 180°

3x= 180 -18

X = 162\3

X = 54°

So angle A = angle B= 54°•

angle C= x+ 18

= 54+18

= 72°.

Step-by-step explanation: