Question

two angles of a triangle are equal and the third angle is greater than each of

those angles by 30. Determine all the angles of the triangle

Answer 1

Let the two equal angles be xGiven that the third angle is 30 greater than the equal angleHence third angle = (x + 30°)Recall that the sum of angles in a triangle is 180°⇒ x + x + (x + 30°) = 180°⇒ 3x + 30° = 180°⇒ 3x = 150°∴ x = 50°Hence (x + 30°) = 50° + 30° = 80°Thus the angles of the triangle are 50°, 50° and 80°.

Answer 2

let equal angles be x degree
x + x + (x +30)=180
3x =180-30
x = 50 degree
all angles are 50, 50 , and 80
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