Two angles of a triangle are equal and the third angle is greater than each one of them by 18°. Find the angles.
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A+A+A+18°=180°,
3A=180°-18°,
3A=162°,
A=162°/3=54°,
1st angle=2nd angle=54°,
3rd angle=54°+18°=72°
3A=180°-18°,
3A=162°,
A=162°/3=54°,
1st angle=2nd angle=54°,
3rd angle=54°+18°=72°
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