Question

two angles of a triangle are equal and the third angle is greater than each one of them by 18 .find the angles

Answer 1

Hey dear here is your answer!!!!!!;

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Let us assume that equal angles are 'x'
Let the third angle by 'y'

According to question;

y= x+ 18

By using Angle sum property :

y+ x + x = 180°
x+18+2x = 180°
3x = 162
x = 54°

Angles are :- 54°, 54° , 72°

Hope it helps u dear..☺️☺️☺️⭐⭐⭐

Answer 2

Two angles of a triangle are equal

so

x = x

and the third angle is greater than 18

so

ATQ

X+X+(X+18)= 180

3X + 18 = 180

3X = 180-18

3X = 162

X = 162 / 3

X = 54

second angle will Also be 54

bcz two angles of a triangle were equal.

Third angle

X +18

= 54 + 18

= 72