Question

two angles of a triangle are equal and the third angle is greater than each one of them by 18° find the angle

Answer 1

Let the first angle=x

second angle=x

third angle=x+18

x+x+x+18=180

3x=180-18

3x=162

x=162/3

=54

54,54,72

Answer 2

✬ Angles = 54° , 54° & 72° ✬

Step-by-step explanation:

Given:

• Two angles of a triangle are equal.
• Third angle is greater than each one by 18°.

To Find:

• What is the measure of all angles?

Solution: Let the equal angles be of x° each. Therefore,

➮ 1st angle = 2nd angle = x°

➮ 3rd angle = (x + 18)°

As we know that

★ Sum of angle of ∆ = 180° ★

$\implies{\rm }$ ( 1st + 2nd + 3rd ) angle = 180°

$\implies{\rm }$ ( x + x + x + 18 ) = 180°

$\implies{\rm }$ 3x + 18 = 180°

$\implies{\rm }$ 3x = 180 – 18

$\implies{\rm }$ 3x = 162

$\implies{\rm }$ x = 162/3

$\implies{\rm }$ x = 54°

So,

➯ Measure of first and second angle is x = 54°

➯ Meaure of third angle = (x + 18)

=> (54 + 18) = 72°

________________________

★ Verification ★

➨ (54° + 54° + 72°) = 180°

➨ (108° + 72°) = 180°

➨ 180° = 180°

$\large\boxed{\texttt{Verified}}$