Two angles of a triangle are equal and the third angle is greater than each one of them by 18 .find the angle
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Answered by
173
Let us assume, third angle of a triangle is y and two angle of a triangle are a and b respectivelly,
Teo angles are equal. Therefore a = b = x
Condition: Sum of three angles = 180
Given:
y = x + 18 ----------1
To satisfy thr condition of a triangle
x + x + y = 180
2x + x + 18 = 180
3x = 162
x = 54
and therefore, y = x + 18 = 54 + 18 = 72
Therefore, three angles of a triangle are 54, 54, 72.
Teo angles are equal. Therefore a = b = x
Condition: Sum of three angles = 180
Given:
y = x + 18 ----------1
To satisfy thr condition of a triangle
x + x + y = 180
2x + x + 18 = 180
3x = 162
x = 54
and therefore, y = x + 18 = 54 + 18 = 72
Therefore, three angles of a triangle are 54, 54, 72.
Answered by
77
Answer:
Step-by-step explanation:
let the equal angles of triangle be x
Therefore,the third angle ATQ will be x+18
x+x+(x+18)=180 (angle sum property of triangle)
3x+18=180
3x=180-18
3x=162
x=162/3
x=54
so Angles in the triangle would be
54,54,
x+18 or 72
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