Question

two angles of a triangle are equal and the third angle is greater than each of those angles by 30 degree determine all the angles of a triangle.

Answer 1

sum of all angles of a triangle is 180°
let the two equal angles be x° and x°

x+x+(x+30°)=180°
3x+30°=180°
3x=180°-30°
3x=150°
x=150°/3
x=50°

Answer 2

Given :-

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30 degree

To Find :-

All angle

Solution :-

Let the angle be x,x and x + 30

x + x + x + 30 = 180

3x + 30 = 180

3x = 180 - 30

3x = 150

x = 150/3

x = 50

Now

1st angle = 2nd angle = 50

3rd abgle = 50 + 30 = 80