Question

Two angles of a triangle are equal and the third angle is 70'. Find the measure of equal angles.​

Answer 1

Solution :

In the above question, it is given that two angles of a triangle are equal and the third angle is 70° .

Let us assume that the equal angles measure x° each .

Now , for a triangle :

Sum of all angles in a triangle is π °s .

So,

x° + x° + 70° = 180°

> 2x° + 70° = 180°

> 2x° = 180° - 70°

> 2x° = 110°

> x° = 110/2 °

> x = 55° .

Thus , the equal angles of this isosceles triangle are 55° and 55° respectively.

This is the required answer.

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Answer 2

$\sf\Large{\underline{\underline{Answer:-}}}$

Given,

• Two Angles of a triangle are equal.
• Third angle is 70°
• Find the measure of equal Angles.

We know that the the sum of the Angles of a triangle is always 180°. And it is given that the third side is 70° , so let's find the other two equal sides.

$\begin{gathered}\\\;\sf{:\rightarrow\;\;\;=\;\bf{{ x \times x + 70} = \large\boxed { \sf \orange{180}}\:}}\end{gathered}$

$\: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;\;=\;\bf{{ 2x + 70} =180\:}}\end{gathered}$

$\: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;\;\bf{{ 2x} = 180 - 70\:}}\end{gathered}$

$\: \: \: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;\;\bf{{ 2x} = 110\:}}\end{gathered}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;\;\bf{x \: = \sf{\cancel\dfrac{110}{2}}}}\end{gathered}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;\;\bf{\large\boxed { \sf \red{x \: = \: 55}}}}\end{gathered}$

${\underline{\underline{\sf{\green{Given,}}}}}$

The other two Angles will be 55° each .