Question

two angles of a triangle are equal and the third angles is lesser then each of there angles by 12°.find all the angles of the triangles

Answer 1

Hi...!

As the first two angles of the triangle are equal , let's assign there values as x°.

The, third angle = 12° lesser = x - 12 °

We know, all angles of a triangle sum up to make 180°.

So, ⇒ x + x + ( x - 12) = 180

⇒3x = 180 + 12

⇒x = 192/3 = 64 °

Thus, we have values of first two angles as 64°

Then, third angle = x - 12 = 64 - 12 = 52°

Answer : first angle = 64°,second angle=64°,third angle=52°

Happy Independence Day...! :)

Answer 2

let angles be x+y+z=180
let x=y
let z = x-12
so Angeles are= x+y+z=180
=x+x+x-12=180
= 3x=180+12
=3x= 192
=x= 64
so first angle x=64 degree
2nd angle y I.e.=x =64 degree
and 3 angle that is x-12=64-12= 52degree.



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