Question

Two angles of a triangle are equal and third angle is greater than each of these angles by 30degree find all the angles of triangle

Answer 1

Answer:

Let the two equal angles be x Given that the third angle is 30 greater than the equal angle Hence third angle = (x + 30°) Recall that the sum of angles in a triangle is 180° ⇒ x + x + (x + 30°) = 180° ⇒ 3x + 30° = 180° ⇒ 3x = 150° ∴ x = 50° Hence (x + 30°) = 50° + 30° = 80° Thus the angles of the triangle are 50°, 50

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Answer 2

Answer:

Let the two angles of the given triangle be x and x.

Then, the third angle would be (x + 30).

A/q, x + x + (x + 30)= 180

      → 3x + 30= 180

      → 3x= 150

      → x= 50

So, The two angles = x = 50

 and, the third angle = x + 30 = 80

Hence, the three angles of the triangle is 50, 50, and 80.