two angles of a triangle are equal and third angle is greater than each one of my 18 degree find the angles
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2x°+x°+18°=180°
3x°+18°=180°
3x°=180°-18°
3x°=162°
x°=162°/3
x°=54°
First angle=54°
second angle=54°
Third angle =54°M + 18°
=72°
3x°+18°=180°
3x°=180°-18°
3x°=162°
x°=162°/3
x°=54°
First angle=54°
second angle=54°
Third angle =54°M + 18°
=72°
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