Question

two angles of a triangle are equal qnd the third is greater than each one of them by 18°.find the angles​

Answer 1

Answer:

x+x+x+18=180

3x=180-18

3x= 162

x= 162/3

x= 54

one angle=54°

2nd angle=54°

3rd angle= 54+18

= 72°

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Answer 2

$\sf\red{SolutioN:-}$

Let the ∠1 be 'x'.

∠1 = ∠2

∠2 = x

Let the ∠3 be x + 18°.

We know that, Sum of all interior angles of triangle = 180°.

⇒x + x + x + 18 = 180°

⇒3x + 18 = 180°

⇒3x = 180 - 18

⇒3x = 162°

⇒x = 162°/3

⇒x = 54°

∠1 = 54°

∠2 = 54°

∠3 = 54° + 18 = 72°

Verification:-

⇒x + x + x = 180°

⇒54° + 54° + 72° = 180°

⇒180° = 180°

Hence , verified.

$\large\tt\red{Therefore,}$

$\large\tt\</strong><strong>p</strong><strong>u</strong><strong>r</strong><strong>p</strong><strong>l</strong><strong>e</strong><strong>{</strong><strong>One</strong><strong>\</strong><strong>:</strong><strong> angle</strong><strong>\</strong><strong>:</strong><strong>is</strong><strong>\</strong><strong>:</strong><strong>5</strong><strong>4</strong><strong>°</strong><strong>}$

$\large\tt\pink{</strong><strong>Secon</strong><strong>d</strong><strong>\: angle\:is\:54°}$

$\large\tt\</strong><strong>b</strong><strong>l</strong><strong>u</strong><strong>e</strong><strong>{</strong><strong>Third</strong><strong>\: angle\:is\:</strong><strong>7</strong><strong>2</strong><strong>°</strong><strong>}$