Question

two angles of a triangle are in the ratio 3 ratio 2. if the sum of these angle is is equal 7/2th of the third, find the angles.​

Answer 1

Step-by-step explanation:

<a= 84°

<b=56°

<c=40°

Proven!

Answer 2

Answer:

24°, 16° and 140°.

Step-by-step explanation:

Let the angles, in ratio, are 3a and 2a.

In question, sum of 3a and 2a is (7/2) of third angle.

Third angle = (7/2){3a + 2a} = (7/2)(5a)

= > third angle = 17.5 a

In triangle, sum of all angles = 180°

= > 3a + 2a + 17.5a = 180°

= > 22.5a = 180°

= > a = 180°/22.5

= > a = 8°

Therefore angles are:

3a = 3(8°) = 24°

2a = 2(8°) = 16°

17.5a = 17.5(8°) = 140°

Angles are 24°, 16° and 140°.