Question

TWO ANGLES OF A TRIANGLE ARE IN THE RATIO OF 4:5 IF THE SUM OF THESE ANGLES IS EQUAL TO THE THIRD ANGLE FIND THE ANGLES OF TRIANGLE​

Answer 1

Answer:

Let the triangle be ABC

Step-by-step explanation:

Given:∆A = 4x ∆B= 56x

∆C = ∆A + ∆B =∆C = 4x +5x=9x By angle sum property ∆A +∆B +∆C =180° =4x + 5x + 9x = 180° 18x = 180° x = 180°/ 18 = 10° = ∆A = 4x =4(10) = 40°

∆B = 5x =5(10) = 50°

∆c = 9x =9(10)= 90°

Answer 2

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