Question

Two angles of a triangle are of equal measure and each is two-fifth the measure of the third angle. Find the three angles of the triangle.​

Answer 1

Answer:

Let the 3rd angle be 'x'

Two equal angles each=2/5 * x

Therefore x+2/5*x+ 2/5*x = 180

x+4/5*x = 180

9x/5 = 180

9x= 180* 5

x = 20* 5

x= 100

Two equal angles are 2/5 * 100 = 40

The three angles are 100, 40 and 40 degrees