Question

two angles of a triangle are the measures 60 and 75 find the measurement of the third angle​

Answer 1

In triangle ABC , angle A= 60° , angle B = 75° , angle C= 180°- (60°+75°) = 45° .

By the sine rule :- a/sin A = b/sinB = c/sinC

a/Sin 60°/a = b/sin75° = c/sin45° = k(let).

a = k.sin60° = k.(√3/2).

b = k.sin75° = k.sin(45°+30°) = k.(sin45°.cos30°+cos45°sin30°)=k.(√3+1)/2√2.

c = k.sin45° = k.(1/√2).

Thus, a. : b : c = k.(√3/2) : k.(√3+1)/2√2 : k.(1/√2). , multiplying by 2√2/k.

or, a : b : c. = (√6) : (√3+1) : (2)

please thanks me

Answer 2

Answer:

first of all thanks for asking this question!! and here is your answer mate ♥️

Step-by-step explanation:

let us take the angles as a,b,c

atq

a=60

b=75

a+b+c=180(angle sum property)

60+75+c=180

135+c=180

c=180-135

c=45