Question

Two angles of a triangles are of equal measure and each is one fourth of the third angle. Find all the angles. ​

Answer 1

Answer:

mark it as BRAINLIEST

Step-by-step explanation:

Let measure of two of its equal angles be x°

And, third angle be y°

Then, x°+x°= y°

But, according to angle sum property of a triange,

Sum of all angles of a triangle = 180°

So, x°+x°+y°= 180°

=> y°+y° = 180°

=> 2y° = 180°

Therefore, y = 90°

Hence, other angles are 45°

We can call this angle as Right isosceles triangle

Answer 2

Step-by-step explanation:

Let the first and second angle be A and B respectively

Third angle ‘C’ = A+B

As we know that sum of all three angles of a triangle is equal to 180.

Therefore,

=> A+B+C = 180°

=> C+C=180°

=> 2C=180°

=> C = 90°

Third angle = 90°

Since, in this question no relation has been defined among the other two angle hence the relationship can not be defined accurately.

Since A+B= 90 possibilities are (A=30, B=60 or A= 45, B=45 pr Many more….)

Hope it helps :)