Question

Two angles of an eight sided polygon are 142’ and 176’ if the remaining angles are equal to each other find the magnitude of each of the equal angles

Answer 1

Answer:

187'degrees

Step-by-step explanation:

Just subtract the sum of these angles from the total angle of that perticular polygon and then divide by the no. Of sides remaining

Answer 2

The magnitude of each equal angles=127 degree

Step-by-step explanation:

Let two angles of an eight sided polygon are

x=142 degrees and y=176 degrees

Number of sides of polygon=n=8

We know that

Number of  angles of polygon=Number of sides

Number of angles of polygon,

Sum of interior angles of polygon=$(n-2)\times 180[/tex</strong>][tex]=(8-2)\times 180=6\times 180=1080^{\circ}$

Let a be the measure of each equal angles of eight side polygon

$142+176+a+a+a+a+a+a=1080$

$318+6a=1080$

$6a=1080-318=762$

$a=\frac{762}{6}=127^{\circ}$

Hence, the magnitude of each equal angles=127 degree

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