Two angles of triamgle are given in ratio 4:5,ifthe sum is equal to third angle find the anglez of triangle
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We know that the sum of the angles of a triangle are 180 (degrees).
Let the measures of two angles of the triangle be 4x, 5x.
Therefore, the third one is 4x + 5x , i.e., the sum of the two angles = 9x.
Now, 4x + 5x + 9x = 180.
Therefore, 18x = 180 and x = 10.
So the first angle (4x) will be 4×10 = 40 (degrees).
The second angle (5x) will be 5×10 = 50
The third angle will be 40+50 = 90.
So the measures of the angles of the triangle are 40 (degrees), 50 (degrees) and 90 (degrees).
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I hope this helps!
We know that the sum of the angles of a triangle are 180 (degrees).
Let the measures of two angles of the triangle be 4x, 5x.
Therefore, the third one is 4x + 5x , i.e., the sum of the two angles = 9x.
Now, 4x + 5x + 9x = 180.
Therefore, 18x = 180 and x = 10.
So the first angle (4x) will be 4×10 = 40 (degrees).
The second angle (5x) will be 5×10 = 50
The third angle will be 40+50 = 90.
So the measures of the angles of the triangle are 40 (degrees), 50 (degrees) and 90 (degrees).
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I hope this helps!
Answered by
34
Let the measure of two angles be 4x and 5x and the third one is ( 4x + 5x ).
We know that ;
Sum of angles of triangle = 180°
⇒ 4x + 5x + 4x + 5x = 180
⇒ 18x = 180
⇒ x = 180/18
⇒ x = 10
Therefore, the angles are ;
4x = 4 * 10 = 40°
5x = 5 * 10 = 50°
9x = 9 * 10 = 90°
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