Question

Two angles of triangle are equal and the third angle is greater than each of those by 30°.find all angles

Answer 1

Answer:Let the two equal angles be x the third angle is 30 more than the equal angle therefore third angle = (x + 30°) sum of angles in a triangle is 180° ⇒ x + x + (x + 30°) = 180° ⇒ 3x + 30° = 180° ⇒ 3x = 150° ∴ x = 50° Hence (x + 30°) = 50° + 30° = 80° Thus the angles of the triangle are 50°, 50° and 80°.

Step-by-step explanation:

Answer 2

Answer:

50°

50°

80°

Step-by-step explanation:

Let say two equal angles of Triangles = A°

Third Angle is greater than each equal angle by 30°

Third Angle = A° + 30°

Sum of all angles = 180°

A° + A° + A° + 30° = 180°

Subtracting 30° from both sides

3A° = 150°

Dividing by 3 both Sides

A° = 50°

Both equal Angles are 50° each

Third Angle = 50° + 30° = 80°

All angles are 50° , 50°  & 80°