Two ants A and B start from a point P on a circle at the same time, with A moving clock-wise and B moving
anti-clockwise. They meet for the first time at 10:00 am when A has covered 60% of the track. If A returns to
at 10:12 am, then B returns to P at
(A) 10:27 am (B) 10:25 am
(C) 10:45 am
(D) 10:18 am
Answers
Answered by
3
Step-by-step explanation:
A takes 12mins to cover ⅖th of the path
when A covers ⅗th, B covers ⅖th
when A covers full, B covers ⅔rd
So in 12mins, B covers ⅔-⅖= 4/15
So the last ⅓rd is covered by B in 12*15/12= 15mins more
So the time when B reaches starting point is 10:12+15mins
= 10:27
Option A is correct
If you are satisfied with the solution pls mark as brainliest
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