two ants of length 1 and 1.2 cm crawl in opposite directions with the average speed 2 and 3 mm per second resp. How many seconds will they take to cross each other
Answers
Answer:
4.4 Sec
Step-by-step explanation:
length of first ant= 1 cm or 10 mm
length of second ant = 1.2 cm or 12 mm
so total distance which need to be covered is 22 mm.
Now speed is 2 mm/sec and 3 mm/sec (Opposite direction), So effective or respective speed will be 5 mm/sec.
Total time to cross eachother = 22/5 sec, which is 4.4 sec
Given : two ants of length 1 and 1.2 cm crawl in opposite directions with the average speed 2 and 3 mm per second respectively .
To Find : How many seconds will they take to cross each other
Solution:
Lengths are 1 cm and 1.2 cm
1 cm = 10 mm
1.2 cm = 12 mm
Total Distance to be covered = 10 + 12 = 22 mm
Moving towards each other hence speed will be added
so Speed =2 + 3 = 5 mm / s
Time = Distance / Speed
=> Time = 22/5
=> Time = 4.4 secs
Hence 4.4 secs will be taken to cross each other.
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