Question

Two ants start simultaneously from two ant holes towards each other. The first ant covered 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant traveled 800 feet to the meeting point.​

Answer 1

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Step-by-step explanation:

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Answer 2

The speed of 2nd ant is 35 feet / hr.

1st Ant covers 8% of 800 Feet in 3 hours.

8% = 800 feet

1% = 100 feet

100% = 10000 feet

∴Total distance = 10000 feet

2nd Ant Covers  (7/120)×10000 in 2 hours 30 minutes i.e 150 Minutes

Implies, 2nd Ant Covers 700 feet in 3 hours

⇒ Both Ants Cover (800+700) = 1500 Feet in 3 Hours

⇒ 1500 Feet = 15% of the total calculated distance in 3 Hours

For 1 Hour two ants cover a Distance = 1500/3 = 500 Feet

∴ `Ant 1 & Ant 2 cover a total distance 10000 feet in = 10000/500

= 20 hours

∴ The speed of 2nd ant = Distance/Time

=700 feet / 20hr

=35 feet / hr