Question

two AP are given 9,7,5.....and 24,21,18..... if nth term of both the progression are equal then find the value of n and nth term

Answer 1

HERE IS YOURS SOLUTION;

◆ an = tn( 'a' is 1st term n 't' is 2nd term )
a+(n-1)d = a+(n-1)d

◆ 1st AP a=9, d =- 2
2nd AP a= 24 , d= -3

◆ 9+(n-1)(-2) = 24+(n-1)(-3)
9-2n+2 = 24 -3n + 3
n = 16

< So, n is 16 >

◆ an = a +(n-1)d

=> an = 9+(16-1)-2

=> an = -21

<So, the value of an is -21>

HOPE IT HELPS

Answer 2

Answer:

n=16 and 16th terms of both A.P.'s=-21

Step-by-step explanation:

You can see detail explanation by watching the video below on youtube

https://www.youtube.com/watch?v=KvsZLdmrpBM