Question

TWO AP's have the same common difference. The first term of one AP is 2
and that of the other is 7. The difference between their 10th terms is the
same as the difference between their 21st terms, which is the same as the
difference between any two corresponding terms? Why?​

Answer 1

Answer:

5

Step-by-step explanation:

because its increasing in the same manner i.e. same common difference..

for e.g.

second term of 1st AP would be 2+x

second term of 2nd AP would be 7+x

and there difference would be

7+x-(2+x)

7+x-2-x

7-2

5

Hope it helps you..

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Answer 2

Answer:

Let the same common difference of two AP’s be d, Given that, the first term of first AP and second AP are 2 and 7 respectively, then the AP’s are

2,2 + d,2 + 2d,2 + 3d,.,.

and  7,7+ d, 7 +2d, 7+3d,…

Now, 10th terms of first and second AP’s are 2 + 9d and 7 + 9 d, respectively.

So, their difference is 7 + 9d – (2 + 9d) = 5

Also, 21st terms of first and second AP’s are 2 + 20d and 7 + 20d, respectively.

So, their difference is 7 + 20d – (2 + 9d) = 5

Also, if the a„ and bn are the nth terms of first and second AP.

Then, bn -an = [7 + (n-1)d)] – [2 + (n-1)d] = 5

Hence, the difference between any two corresponding terms of such AP’s is the same as the difference between their first terms.