Question

Two applications of rating 100 watts - 200volts and 400 watts - 220 volts are joined in series to a 220 volts supply total power consumed ( in watts ) in the circuit is

Answer 1

Answer:

Answer:

For bulb 1

P = 200 watt

V = 250 V

I = P/V

I = 200/250

I = 0.8 A

R = V/I

R = 250/0.8

R = 312.5 ohm

For bulb 2

P = 100 watt

V = 250 V

I = P/V

I = 100/250

I = 0.4 A

R = V/I

R= 250/0.4

R = 625 ohm

Total resistance in circuit = 625 + 312.5

= 937.5 ohm

Total power consumed, P = V²/R

= 250 × 250/937.5

= 66.66 watt or 67 watt

PLEASE MARK IT BRAINILIEST