Two APs have same common different . the different between their 100th term is 100,what is the difference between their 1000th terms?
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To Find :
- we need to find the difference between 1000 th term if the two AP's have same common difference.
Given :
- Two AP's have same common difference .
- Difference between their 100th term is 100.
Let the common difference be d and first term of 1st AP be a and First term of 2nd AP be a2.
Now
As we know that,
- an = a + (n - 1)d
100th term of 1st AP :-
= a + (100 - 1)d
= a + 99d.
100th term of 2nd AP is a2 + 99d
As it is given in the Question that difference between their 100th term is 100
So,
➔ a + 99d -(a2 + 99d) = 100
➔ a + 99d - a2 - 99d = 100
➔ a - a2 = 100 .........1)
Now,
Finding difference between their 1000th term
- 1000th term of 1st AP = a + 999d
- 1000th term of 2nd AP = a2 + 999d
So,
➔ a + 999d - (a2 + 999d)
➔ a + 999d - a2 - 999d
➔ a - a2
From equation...1)
› a - a2 = 100
So,
Difference between their 1000th term is 100 .
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