two APs have the same Common d the fist term one of these is 8 and that of other is 15 what is the difference between their 40th term
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a1=8. a2=15
let common difference be d
an=8+(40-1)d. an=15+(40-1)d
=8+39d. =15+39d
difference between their 40th tetm= 8+39d-15-39d
=-7
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let common difference be d
an=8+(40-1)d. an=15+(40-1)d
=8+39d. =15+39d
difference between their 40th tetm= 8+39d-15-39d
=-7
HOPE IT HELPS YOU
MARK ME AS THE BRAINLIS.......
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