Two APs have the same common difference. The difference between their 100th terms is
100, what is the difference between their 1000th terms?
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Answer:
100
Step-by-step explanation:
Let the common difference of both the APs be d and d' respectively. And the first terms be a and A respectively.
ATQ,
d = d' ....... equation 1
Also it's given that,
a100 - A100 = 100
{a + (n - 1 ) d} - {A + (n - 1) d'} = 100
[since an = a + (n - 1 ) d]
{a + (100 - 1) d} - {A + (100 - 1) d'} = 100
a + 99d - A - 99d' =100. (from 1)
a - A = 100 ........equation 2
now,
a 1000 - A1000
a + (n-1)d - { A + (n-1) d'}
a + (1000 - 1)d -{A + (1000-1) d'}
a + 999d - { A + 999d'}
a + 999d - A - 999d'
a - A (from 1)
100. (from2)
Hope it helps
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