Two APs have the same common difference. The first term of one of these is -1 and that of other is -8. What is the difference between their 4th terms
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Answered by
2
Hey mate,
the answer will be 7.
Step-by-step explanation:
Let a be the first term of first AP.
Therefore, a' be the first term of second AP.
Given that,
a= -1
a'= -8
Common difference of both the APs are same i.e., d.
Difference between the first terms of both APs
a- a'= -1-(-8)=-1+8=7
We know that fourth term of an AP can be written as "a+3d"
Therefore difference between the fourth terms of both APs, will be
Fourth term of first AP - Fourth term of second AP
a+3d-(a'+3d)= a+3d-a'-3d
Cancelling 3d, we get,
a-a'= -1-(-8)=-1+8=7
Answered by
0
Step-by-step explanation:
ok
this u have to take
ovgo
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