two are thrown vertically upwards simultaneously with initial velocity 10m/s &20m/s respectively find the height attained by themthem
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given,u=10m/s ,v=20m/s take g as 9.8m/s²
Now,use third equation v²=u²+2gh
(20)²=(10)²+2*9.8*h
400=100+19.6h
400-100=19.6h
300=19.6h
300/19.6=h
15.30...=h
Hence proved
Now,use third equation v²=u²+2gh
(20)²=(10)²+2*9.8*h
400=100+19.6h
400-100=19.6h
300=19.6h
300/19.6=h
15.30...=h
Hence proved
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