Two arithmetic progression has the same common difference. If the first term of the first progression is 3 and that of the another is 6. Then the difference between their 4ᵗʰ term is
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Answer:
a4 (first progression) = 3+(4-1) d
= 3+3d
a4(second progression) = 6+(4-1) d
= 6+3d
difference= 3+3d - (6+3d)
= 3 + 3d - 6 -3d
= 3 - 6
= - 3
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In two arithmetic progressions,
Provided that:
- 1st term of 1st AP = 3
- 1st term of 2nd AP = 6
To calculate:
• Difference between their 4th term
Solution:
• Difference between their 4th term = -3
Required solution:
→ 1st term of 1st AP = 3
→ Fourth term = (3 + 3d)
→ 1st term of 2nd AP = 6
→ Fourth term = (6 + 3d)
The difference between their 4th term is
→ Fourt term of 1st AP - Fourth term of 2nd AP
→ (3+3d) - (6+3d)
→ 3 + 3d - 6 - 3d
→ 3 - 6
→ -3 is the difference between their 4th term.
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