Question

Two arithmetic progression has the same common difference. If the first term of the first progression is 3 and that of the another is 6. Then the difference between their 4ᵗʰ term is​

Answer 1

Answer:

a4 (first progression) = 3+(4-1) d

= 3+3d

a4(second progression) = 6+(4-1) d

= 6+3d

difference= 3+3d - (6+3d)

= 3 + 3d - 6 -3d

= 3 - 6

= - 3

Answer 2

In two arithmetic progressions,

Provided that:

• 1st term of 1st AP = 3
• 1st term of 2nd AP = 6

To calculate:

• Difference between their 4th term

Solution:

• Difference between their 4th term = -3

Required solution:

→ 1st term of 1st AP = 3

→ Fourth term = (3 + 3d)

→ 1st term of 2nd AP = 6

→ Fourth term = (6 + 3d)

The difference between their 4th term is

→ Fourt term of 1st AP - Fourth term of 2nd AP

→ (3+3d) - (6+3d)

→ 3 + 3d - 6 - 3d

→ 3 - 6

→ -3 is the difference between their 4th term. $\:$