Math, asked by stardustxo, 9 hours ago

Two arithmetic progressions has the same common difference. If the first term

of the first progression is 3 and that of the other is 8, then the difference between

their 3rd term is

A. 2
B. 3

C. 4
D. 5​

Answers

Answered by LoverBoy346
11

Answer:

d.5

Step-by-step explanation:

 \color{orange} \boxed{  \color{blue}\boxed{ \mathbb{ \colorbox{red}{ \color{yellow}Given :-}}}}

 :  \implies  \: first  \: term  \: of  \: the \:  first  \: AP, a= 3

  : \implies first  \: term \:  of  \: second  \: AP , a'  = 8

Now, term of first AP

 \implies \: a_3 = 3 + (3 - 1)d

 \implies \: a_3 = 3 + 2d

Third term of second AP,

a'_3 = 8 + (3 - 1)d

a'_3 = 8 + 2d

According to the question, difference of their third term

 \implies \: a'_3 - a_3

 \implies \: (8 + 2d) - (3 + 2d)

 \implies \: 8 + 2d - 3 - 2d

 \implies \: \boxed{ 5}

Hence the difference between their third terms is 5, and option d is correct one

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