Two arithmetic progressions have equal common differences. The first term of one of these is 3 and
that of the other is 8, then the difference between their 100th terms is
(1) 4
(2) 5
(3) 6
(4) 3
Answers
Answered by
1
ANSWER
Let the common difference of the two APs be d.
Then, their nth terms are
a
n
=3+(n−1)d and b
n
=8+(n−1)d
a
n
−b
n
=[3+(n−1)d]−[8+(n−1)d]
a
n
−b
n
=3+(n−1)d−8−(n−1)d
a
n
−b
n
=3−8
a
n
−b
n
=−5 for all n∈N
Therefore,
a
2
−b
2
=−5
Answered by
0
Step-by-step explanation:
8- ( n-1) I hope this is right
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