Question

Two arithmetic progressions have the same common difference.
If their first terms are respectively 41 and 42, then the numerical
difference of their 52nd terms will be​

Answer 1

Answer:

as in the AP with every number the common difference is always same therefore the common difference if this AP will be 42-41 =1 therefore the common difference will be 1...

Answer 2

Step-by-step explanation:

For first A.P

S1

n

=(

2

n

)(2n+(n−1)d)

S1

30

=(

2

30

)(2×3+(30−1)d)

S1

30

=15(6+29d)

S1

30

=90+435d

For second AP

S2

n

=(

2

n

)(2n+(n−1)d)

S2

30

=(

2

30

)(2×8+(30−1)d)

S2

30

=15(16+29d)

S2

30

=240+435d

Difference between S1

30

−S2

30

=(90+435d)−(240+435d)=150