Question

Two army persons A and B each of weight of 500 N climb up a rope through a height of 10 m. A takes 20 s while B takes 40 s to achieve this task. What is ratio of the powers of person A and B?​

Answer 1

Answer:

correct ans is

2:1

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Answer 2

Given:

Weight of person A and B, $F= 500 N$

height, $s = 10 m$

time taken by A to achieve the task, $t_{a} = 20 s$

time taken by B to achieve the task, $t_{b} = 40 s$  

To Find:

We are asked to find the ratio of power of person A and B.

Solution:

We know that

$Power=\frac{W}{t}=\frac{F*s}{t}$

Power of person A,

$P_{a}=\frac{F*s}{t_{a} }=\frac{500*10}{20}=250 watts$

Power of person B,

$P_{b}=\frac{F*s}{t_{b} }=\frac{500*10}{40}=125 watts$

Ratio of the powers,

$\frac{P_{a} }{P_{b} }=\frac{250}{125}=\frac{2}{1}=2:1$

Hence the ratio of powers of person A and B is $2:1$

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