Question

two articles are sold at rs 198 each such that a profit of 10% is made on the first whils a loss of 10% is incured on the other, what would be the net profit/loss on the two transaction combined

Answer 1

cost of loss making article =a
.... profit making. =b
198=a-a/10
1980=9a
a=220

198=b+b/10. (10%=1/10)
1980=11b
b=180

loss on a=220-198=22
gain on b=198-180=18

hence net loss=22-18=₹4

Answer 2

Given : Two articles are sold at rs 198 each such that a profit of 10% is made on the first, while a loss of 10% is incurred on the other. .

To find : The net profit/loss on the two transaction combined.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the net profit or loss)

Let,

the cost price of the first article = Rs. x

and, the cost price of the second article = Rs. y

For the first transaction :

• Profit amount = x × 10% = x × (10/100) = Rs. x/10
• Selling price = x + (x/10) = (10x + x)/10 = Rs. 11x/10

For the second transaction :

• Loss amount = y × 10% = y × (10/100) = Rs. y/10
• Selling price = y - (y/10) = (10y-y)/10 = Rs. 9y/10

According to the data mentioned in the question,

11x/10 = 198

x = 198 × (10/11)

x = 180

So, cost price of the first article = Rs. x = Rs. 180

Similarly,

9y/10 = 198

y = 198 × (10/9)

y = 220

So, cost price of the second article = Rs. y = Rs. 220

Total cost price :

= Cost price of the first article + Cost price of the second article

= Rs. (180 + 220)

= Rs. 400

Total selling price :

= Selling price of 1 article × Number of articles sold

= Rs. (198 × 2)

= Rs. 396

The total selling price is less than the total cost price. That's why, there will be a loss.

Loss amount :

= Total cost price - Total selling price

= Rs. (400 - 396)

= Rs. 4

Loss percent :

= 100 × (Loss amount / Total cost price)

= 100 × (4/400)

= 1%

(This will be considered as the final result.)

Hence, there will be a net loss of 1%