Question

Two bags contain 5 blue and 7 green balls and 3 blue and 9 green balls,respecvely.
One ball is transferred the first bag to the second bag and then one ball is drawn from the second bag. Find the probability that the first ball transferred is green (Given that the ball drawn is green)
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Answer 1

Answer:

no of green balls by/ total ball

9/5+7+3+9

9/24

3)8

Answer 2

Answer:

Total number of balls:5+7+3+9=24

Step-by-step explanation:

So, Probability of getting a green ball from the bag= Number of outcomes

Total number of balls

=16/24

Thus 16/24 is the probability of getting a green ball