Two bags had 100 kilograms of sugar each. After taking out 3 times as much sugar from bag one than bag two, bag one had half as much sugar left as bag two. How much sugar is left in each bag?
Answers
Answered by
3
Answer:
Let x be the amount of sugar taken from bag 2
Therefore amount of sugar left in bag two=100-x
Now,ATQ
3x=1÷2(100-x)
3x=(100-x)÷2
6x=100-x
7x=100
x=100÷7=14.2
Therefore sugar left in bag 1 = 100-3x
=100-4.26
=57.4=57kg 4gm
And sugar left in bag 2 =100-x
=100-14.2
=85.8=85kg 8gm
hannjr:
I would disagree with this answer. If x = 20 kg then bag1 has 40 kg left (100 - 3 * 20*) and bag 2 has 80 kg left (100 -20)
Let B1 = 100 - 3 x and B2 = 100 - x. Subtracting equations gives B2 - B1 = 2 x also B1 now = B2 / 2 substituting this in the previous equation and solving for x gives x = B2 /4 then from above where B2 = 100 - x -------- B2 = 100 - B2 /4 and B2 = 80 and x = 20
Ya sorry I had to take 100-3x instead of 3x by mistake
Answered by
3
Ur eq will be
50 - 3x = 1/2 (50-x)
Multiply both sides by 2 (to eliminate the 1/2)
100-6x= 50-x
Add 6x to both sides
100= 50-5x
Subtract 50 from both sides
50=5x
Lastly, divide by 5
10=x
So, 10 kg of sugar was removed from bag 2.
3x= 30, so 30 kg of sugar was removed from bag 1.
50-30=20 kg remaining in bag 1.
50-10=40 kg remaining in bag 2
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